There is a string, , of lowercase English letters that is repeated infinitely many times. Given an integer, , find and print the number of letter a
's in the first letters of the infinite string.
Example
The substring we consider is , the first characters of the infinite string. There are occurrences of a
in the substring.
Function Description
Complete the repeatedString function in the editor below.
repeatedString has the following parameter(s):
Returns
a
in the substringInput Format
The first line contains a single string, .The second line contains an integer, .
Constraints
Sample Input
Sample Input 0
aba
10
Sample Output 0
7
Explanation 0The first letters of the infinite string are abaabaabaa
. Because there are a
's, we return .
Sample Input 1
a
1000000000000
Sample Output 1
1000000000000
Explanation 1Because all of the first letters of the infinite string are a
, we return .
func repeatedString(s: String, n: Int) -> Int {
let a = s.filter { $0 == Character("a") }.count
var cnt = (n/s.count)*a
for i in 0..<n%s.count {
if s[s.index(s.startIndex, offsetBy: i)] == Character("a") {
cnt += 1
}
}
return cnt
}