increase(X) − counter X is increased by 1,
max counter − all counters are set to the maximum value of any counter.
A non-empty array A of M integers is given. This array represents consecutive operations:
if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
if A[K] = N + 1 then operation K is max counter.
For example, given integer N = 5 and array A such that:
A[0] = 3
A[1] = 4
A[2] = 4
A[3] = 6
A[4] = 1
A[5] = 4
A[6] = 4
the values of the counters after each consecutive operation will be:
(0, 0, 1, 0, 0)
(0, 0, 1, 1, 0)
(0, 0, 1, 2, 0)
(2, 2, 2, 2, 2)
(3, 2, 2, 2, 2)
(3, 2, 2, 3, 2)
(3, 2, 2, 4, 2)
The goal is to calculate the value of every counter after all operations.
Write a function:
def solution(N, A)
that, given an integer N and a non-empty array A consisting of M integers, returns a sequence of integers representing the values of the counters.
Result array should be returned as an array of integers.
For example, given:
A[0] = 3
A[1] = 4
A[2] = 4
A[3] = 6
A[4] = 1
A[5] = 4
A[6] = 4
the function should return [3, 2, 2, 4, 2], as explained above.
Write an efficient algorithm for the following assumptions:
N and M are integers within the range [1..100,000];
each element of array A is an integer within the range [1..N + 1].
-두번째 풀이
def solution(N, A):
# write your code in Python 3.8.10
num_dic = {}
max_num = 0
for num in A:
num-=1
if num >= N:
max_num +=find_max(num_dic)
num_dic={}
elif num in num_dic:
num_dic[num]+=1
else:
num_dic[num] = 1
num_list= [max_num]*N
for key in num_dic.keys():
num_list[key] += num_dic[key]
return num_list
def find_max(num_dic):
max_val = 0
for key in num_dic.keys():
max_val = max(max_val,num_dic[key])
return max_val