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yeonkΒ·2022λ…„ 3μ›” 4일
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πŸ’‘ MySQL






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SELECT ANIMAL_OUTS.ANIMAL_ID, ANIMAL_OUTS.NAME
FROM ANIMAL_OUTS
LEFT JOIN ANIMAL_INS 
ON ANIMAL_OUTS.ANIMAL_ID = ANIMAL_INS.ANIMAL_ID
WHERE ANIMAL_INS.DATETIME > ANIMAL_OUTS.DATETIME
ORDER BY ANIMAL_INS.DATETIME ASC;

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