π‘ Python 3
μ½μμ ν© [Link]
def solution(n):
answer = 0
for i in range(1, n+1):
if n == 0: break
elif n % i == 0: answer += i
return answer
μ μλ μμ μ λ°λ§ νμΈνλ μ½λ.. λλ°!!
def sumDivisor(num):
return num + sum([i for i in range(1, (num // 2) + 1) if num % i == 0])