💡 Python 3
신고 결과 받기 [Link]
def solution(id_list, report, k):
from collections import Counter
result = [0] * len(id_list)
u = []
check = {}
for r in set(report):
x, y = r.split()
u.append(y)
if y not in check.keys():
check[y] = [x]
else:
check[y].append(x)
for key, value in Counter(u).items():
if value >= k:
for i in check[key]:
result[id_list.index(i)] += 1
return result
푸는 과정은 내가 생각한 것과 비슷한데 훨씬 간결하고 보기 좋게 푸셨다.
나도 요렇게 풀고 싶었는데. .ㅎㅎ 열심히 공부해야지..^^..
def solution(id_list, report, k):
answer = [0] * len(id_list)
reports = {x : 0 for x in id_list}
for r in set(report):
reports[r.split()[1]] += 1
for r in set(report):
if reports[r.split()[1]] >= k:
answer[id_list.index(r.split()[0])] += 1
return answer