https://school.programmers.co.kr/learn/courses/30/lessons/68644
프로그래머스 레벨1 정답률65%

a=[2,1,3,4,1]

from itertools import combinations
b=list(combinations(a, 2))
print(b)

1. a에서중복제거

a2=list(set(a))
print(a2)

2. 중복 제거 후 콤비네이션

from itertools import combinations
a3=list(combinations(a2, 2))
print(a3)

3. 각 콤비네이션 합

a3list=[]
for i in a3:
k=i[0]+i[1]
#a3list.append(str(i[0][0]+i[0][1]))
if k not in a3list:
a3list.append(k)
print(a3list)

#정리

from itertools import combinations
a2=list(set(numbers))
a3=list(combinations(a2, 2))
a3list=[]
for i in a3:
k=i[0]+i[1]
#a3list.append(str(i[0][0]+i[0][1]))
if k not in a3list:
a3list.append(k)
print(a3list)

정리2

from itertools import combinations

def solution(numbers):
a2=list(set(numbers))
a3=list(combinations(a2, 2))
a3list=[]
for i in a3:
k=i[0]+i[1]
if k not in a3list:
a3list.append(k)

answer = a3list
return answer

#결과 중복제거를 먼저하니까 1+1=2 같은 것이 삭제되는 문제 발생
from itertools import combinations
numbers=[2,1,3,4,1]

def solution(numbers):

a2=list(set(numbers))
a3=list(combinations(a2, 2))
a3list=[]
for i in a3:
    k=i[0]+i[1]
    if k not in a3list:
        a3list.append(k)
         
answer = a3list
return answer

solution(numbers)

중복제거를 안하고 콤비네이션

from itertools import combinations
numbers=[2,1,3,4,1]
def solution(numbers):
a3=list(combinations(numbers, 2))
a3list=[]
for i in a3:
k=i[0]+i[1] #튜플에서각원소뽑아서합
if k not in a3list:
a3list.append(k)
answer = sorted(a3list) # 오름차순정렬
return answer
print(solution(numbers))

제출 100점

from itertools import combinations
def solution(numbers):
    a3=list(combinations(numbers, 2))
    a3list=[]
    for i in a3:
        k=i[0]+i[1] #튜플에서각원소뽑아서합
        if k not in a3list:
            a3list.append(k)
    answer = sorted(a3list) # 오름차순정렬
    return answer