Q.

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in. Additionally, if the number is negative, return 0 (for languages that do have them).

Note: If the number is a multiple of both 3 and 5, only count it once.

A)

function solution(number){
  let arr = [];
    for (let i = 3; i < number; i++) {
      if (i % 3 === 0 && i % 5 === 0)
        arr.push(i);
      else if (i % 3 === 0)
        arr.push(i);
      else if (i % 5 === 0)
        arr.push(i);
      else
        continue;
    }
  
  return arr.reduce((sum, cur)=> sum + cur, 0);
}