def solution(numbers, hand):
leftnow = '*'
rightnow = '#'
answer = ''
def calclen(now, number) :
# 나는 그냥 숫자로 계산했지만, dict 자료형을 활용해 각 숫자를 좌표로 바꾸어 계산할 수 있다!
# dic = {1: [0, 0], 2: [0, 1], 3: [0, 2],
# 4: [1, 0], 5: [1, 1], 6: [1, 2],
# 7: [2, 0], 8: [2, 1], 9: [2, 2],
# '*':[3, 0], 0: [3, 1], '#': [3, 2]}
if number == 0 :
number = 11
if now == 0 :
now = 11
if now == '*' :
now = 10
if now == '#' :
now = 12
initalLen = abs(now-number)
col = initalLen //3
row = initalLen % 3
calcedLen = col + row
return calcedLen
for number in numbers :
if (number == 1 or number == 4 or number== 7):
#얘를 if number in [1,4,7]이렇게 바꿀 수 있다
answer += 'L'
leftnow = number
elif (number == 3 or number == 6 or number== 9):
answer += 'R'
rightnow = number
else :
leftlen = calclen(leftnow, number)
rightlen = calclen(rightnow, number)
if leftlen < rightlen :
answer += 'L'
leftnow = number
elif leftlen > rightlen :
answer += 'R'
rightnow = number
else :
if hand == 'right' :
answer += ('R')
rightnow = number
else :
answer += ('L')
leftnow = number
return answer