nums
정렬function largestPerimeter(nums: number[]): number {
const sortedNums = nums.toSorted((a, b) => b - a)
let maxPerimeter = 0
for(let i = 0; i < sortedNums.length - 2; i++) {
const p1 = sortedNums[i]
const p2 = sortedNums[i + 1]
const p3 = sortedNums[i + 2]
if(p2 + p3 <= p1) continue
maxPerimeter = Math.max(maxPerimeter, p1 + p2 + p3)
}
return maxPerimeter
};