
nums 순회function numberOfPairs(nums: number[]): number[] {
const frequent = new Map()
for(const num of nums) {
frequent.set(num, (frequent.get(num) ?? 0) + 1)
}
let formed = 0
let left = 0
for(const [key, value] of frequent) {
formed += Math.floor(value / 2)
left += value % 2
}
return [formed, left]
};