
nums 순회0과 근접하며, 가장 큰 수 반환function findClosestNumber(nums: number[]): number {
let minGap = Infinity
let maxVal = -Infinity
for(const num of nums) {
const abs = Math.abs(num)
if(abs > minGap) continue
if(minGap === abs) {
maxVal = Math.max(maxVal, num)
continue
}
minGap = abs
maxVal = num
}
return maxVal
};