내 풀이

dartResult를 점수별로 구분해서 풀었따.

const result
[ '1S', '2D*', '3T' ]
이런식으로 나오게!


/(\d+[SDT])([*#]?)/g 정규식을 이용했다.

function solution(dartResult) {
let answer=[]
const pattern = /(\d+[SDT])([*#]?)/g;
const result = dartResult.match(pattern);
  //[ '1S', '2D*', '3T' ]

    
    for(let i=0;i<3;i++){
       const num= parseInt(result[i]) //1
       const bonus = result[i].replace(num, ''); //'S' 또는 'S*'
      
        if(bonus.includes('S')){ //점수계산
           answer.push(Math.pow(num, 1)) 
        }else if(bonus.includes('D')){
            answer.push(Math.pow(num, 2)) 
        }else{//'T'
             answer.push(Math.pow(num, 3)) 
        }
        
        if(bonus.includes('*')||bonus.includes('#')){
          if( bonus.includes('*')){
               answer[i-1]=answer[i-1]*2
           answer[i]=answer[i]*2
          }else{
              answer[answer.length-1]=answer[answer.length-1]*(-1)
          } 
           
        }
        
    }
     
     
    return answer.reduce((a,c)=>a+c,0)
}

다른 풀이

function solution(dartResult) {
    const bonus = { 'S': 1, 'D': 2, 'T': 3 },
          options = { '*': 2, '#': -1, undefined: 1 };

    let darts = dartResult.match(/\d.?\D/g);
    console.log(darts) //	[ '1S', '2D*', '3T' ]

    for (let i = 0; i < darts.length; i++) {
      let split = darts[i].match(/(^\d{1,})(S|D|T)(\*|#)?/),
        score = 
          Math.pow(split[1], bonus[split[2]]) * options[split[3]]
      
//console.log(split)
        //[ '1S', '1', 'S', undefined, index: 0,
      //input: '1S', groups: undefined ]
      
        if (split[3] === '*' && darts[i - 1]) 
          darts[i - 1] *= options['*'];

        darts[i] = score;
    }

    return darts.reduce((a, b) => a + b);
}