>>> t1 = (1, 2, 'a', 'b')
>>> t1[0]
1
>>> t1[]3
'b'
>>> t1 = (1, 2, 'a', 'b')
>>> t1[1:]
(2, 'a', 'b')
>>> t2 = (3, 4)
>>> t1 + t2
(1, 2, 'a', 'b', 3, 4)
>>> t2 * 3
(3, 4, 3, 4, 3, 4)
>>> t1 = (1, 2, 'a', 'b')
>>> len(t1)
4
>>> a = {1: 'a'}
>>> a[2] = 'b'
>>> a
{1: 'a', 2: 'b'}
>>> a['name'] = 'pey'
>>> a
{1: 'a', 2: 'b', 'name': 'pey'}
>>> del a[1]
>>> a
{'name': 'pey', 2: 'b'}
>>> grade = {'pey': 10, 'julliet': 99}
>>> grade['pey']
10
>>> a = {'name': 'pey', 'phone': '109993323', 'birth': '1118'}
>>> a.keys()
dict_keys(['name', 'phone', 'birth'])
>>> list(a.keys())
['name', 'phone', 'birth']
>>> a.values()
dict_values(['pey', '0119993323', '1118'])
>>> a.items()
dict_items([('name': 'pey'), ('phone': '0119993323'), ('birth', '1118')])
>>> a.clear()
>>> a
{}
>>> grade = {'pey': 10, 'julliet': 99}
>>> grade.get('pey')
10
찾으려는 값이 없는 경우 디폴트 값을 정해 사용할 수 있다.
>>> grade.get('john','wrong')
'wrong'
>>> a = {'name': 'pey', 'phone': '109993323', 'birth': '1118'}
>>> 'name' in a
True
>>> 'email' in a
False