🇺🇸 Write a function commonCharacters(string1, string2) which takes two strings as arguments and returns a string containing the characters found in both strings (without duplication), in the order that they appeared in string1.

• Has to return a string. Remember to skip spaces and characters you have already encountered!

🇦🇷 Escribe la función commonCharacters(string1, string2) que recibe dos strings como argumentos y devuelve un string que contiene los caracteres existentes en ambos strings (sin repeticion), en el orden que aparecen en string1.

• Debe retornar un string. Recuerda eliminar los espacion y los caracteres que ya fueron encontrados!

🇰🇷 두 개의 문자열을 인수로 받고 두 문자열(중복 문자 없이)에서 존재하는 문자들을 합한 문자열 반환하는 함수를 작성하세요 (commonCharacters(string1, string2)). 반환값은 문자열1에 나타난 순서대로 나오게 하십시오.

• string을 반환해야 한다. 띄어쓰기를 제거하는 것과 이미 찾은 문자들을 생략해야 하는 것을 기억하십시오!

Example:

// Test
var commonCharacters = function('acexivou', 'aegihobu');

console.log(commonCharacters);
// return -> 'aeiou'

# START [ here ] 🏁

var commonCharacters = function(string1, string2) {
  // Your CODE
};

// Test
commonCharacters("acexivou", "aegihobu"); // output> "aeiou"
commonCharacters("aeiou", "aaeeiioouu"); // output> "aeiou"
commonCharacters("i am a string", "i am also a string"); // output> "i am strng"
commonCharacters("vicapow", "wopaciv"); // output> "vicapow"

# Javascript solution 🏆

• Run it on your browser console window (F12) 🖥
• Please feel free to add your preference language solution 👩‍👩‍👧‍👦
• Do your best to complete the problem 🎭
• if you can't beat this the solution is below 😱

Click for the solution 👇

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SOLUTION

var commonCharacters = function(string1, string2) {
  // TODO: Your code here!
  // new result array []
  let temp = [];
  let result = "";

  if (string1 === string2) {
    result = string1;
  } else if (string1.length === 0 || string2.length === 0) {
    result = "";
  } else {
    // two for loops
    for (let i = 0; i < string1.length; i++) {
      for (let j = 0; j < string2.length; j++) {
        // if statement ? string1 char is equal to string2 char
        // && is not inside result array
        // TRUE> push to result array
        if (string1[i] === string2[j] && !temp.includes(string2[j])) {
          temp.push(string2[j]);
        }
      }
    }
    // Convert temp array into String
    result = temp.join("");
  }
  return result;
};