22.03.24 Day39

C++ 프로그래밍

Class 복습

#include<iostream>
#include<string.h>
using namespace std;
class MyClass 
{
private:
	int age;
	char id;
	char name[10];
public:
	void get();
	void set(int a, char b, const char* c);
};
void MyClass::get()
{
	cout << "나이:" << age << endl << "id:" << id<< endl << "이름:" << name << endl;
}
void MyClass::set(int a, char b, const char* c)
{
	age = a;
	id = b;
	strcpy(name, c);
}
int main()
{
	MyClass o;
	o.set(10, 'C', "oyb");
	o.get();
	return 0;
}

1) set 함수를 다음과 같이 구현하면 오류 발생 set(int a,char b,const charc);
2) c를 const char로 선언해줘서 해결
--> set(int a, char b, const char c) {age=a; id=b; strcpy(name,c);}

Class(생성자)

#include<iostream>
#include<string.h>
using namespace std;
class myclass 
{
private:
	int age;
	char id;
	char name[10];
public:
	myclass();
	myclass(char aid, int aage, const char* aname);
	void get();
	void set(int a, char b, const char* c);
};
myclass::myclass()
{
	age = 999;
	id = 'A';
	strcpy(name, "생성자");
}

void myclass::get()
{
	cout << "나이:" << age << endl << "id:" << id<< endl << "이름:" << name << endl;
}
void myclass::set(int a, char b, const char* c)
{
	age = a;
	id = b;
	strcpy(name, c);
}
int main()
{
	myclass o;
	cout << "생성자에 의한 초기화" << endl;
	o.get();
	cout << endl;

	o.set(10, 'c', "oyb");
	cout << "set 함수에 의한 초기화" << endl;
	o.get();
	return 0;
}

Class(Calc)

#include<iostream>
using namespace std;
class Mycalc
{
private:
	int num1;
	int num2;
public:
	Mycalc();
	Mycalc(int n1, int n2);
	int add();
	int sub();
	int mul();
	double div();
};
Mycalc::Mycalc(int n1, int n2) :num1(n1), num2(n2)
{
	cout << "매개변수 있는 생성자 호출" << endl << n1 << "," << n2 << endl;
}
Mycalc::Mycalc()
{
	cout << "생성자 호출" << endl;
}
int Mycalc::add()
{
	return num1 + num2;
}
int Mycalc::sub()
{
	return num1 - num2;

}
int Mycalc::mul()
{
	return num1 * num2;

}
double Mycalc::div()
{
	return double(num1) / double(num2);

}
int main()
{
	Mycalc c;
	Mycalc d(2, 3);
	cout << d.add() << endl;
	cout << d.sub() << endl;
	cout << d.mul() << endl;
	cout << d.div() << endl;
	return 0;
}

프로그래머스

• 배열뒤집기

  

def solution(num_list):
    answer = num_list
    answer.reverse() # answer=num_list.reverse() 처럼은 못씀
                    # num_list.reverse()하면 그냥 num_list 배열이 뒤집히는것
    return answer

solution([1,2,3,4,5])

1) answer=num_list.reverse()처럼 쓰려고함
2) num_list.reverse()하면 그냥 num_list배열이 뒤집히는거지 대입 불가능