https://www.acmicpc.net/problem/17836
Fail 이라고 출력해야 하는데 fail 로 출력한걸 모르고 1시간을 더 날렸네 하...
import java.io.*;
import java.util.*;
class Pos
{
int r;
int c;
public Pos() {}
public Pos(int r, int c) {
this.r = r;
this.c = c;
}
}
public class Main
{
public static void main(String[] args) throws IOException
{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] input = br.readLine().split(" ");
int N = Integer.parseInt(input[0]);
int M = Integer.parseInt(input[1]);
int T = Integer.parseInt(input[2]);
int[][] castle = new int[N][M];
for(int i = 0; i < N; ++i)
{
input = br.readLine().split(" ");
for(int j = 0; j < M; ++j)
{
castle[i][j] = Integer.parseInt(input[j]);
}
}
int[][] dir = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};
int[][] visit = new int[N][M];
for(int i = 0; i < N; ++i)
{
Arrays.fill(visit[i], -1);
}
int ans = Integer.MAX_VALUE;
ans = Math.min(ans, bfs(new Pos(0, 0), N, M, T, castle, visit, dir, true));
for(int i = 0; i < N; ++i)
{
Arrays.fill(visit[i], -1);
}
ans = Math.min(ans, bfs(new Pos(0, 0), N, M, T, castle, visit, dir, false));
if(Integer.MAX_VALUE == ans)
System.out.println("Fail");
else
System.out.println(ans);
}
private static int bfs(Pos start, int N, int M, int T, int[][] castle, int[][] visit, int[][] dir, boolean getGram)
{
Queue<Pos> que = new LinkedList<>();
que.add(start);
visit[start.r][start.c] = 0;
castle[start.r][start.c] = 0;
boolean gram = false;
boolean princess = false;
Pos end = new Pos(N-1, M-1);
while(que.isEmpty() == false)
{
Pos cur = que.poll();
for(int i = 0; i < 4; ++i)
{
int r = cur.r + dir[i][0];
int c = cur.c + dir[i][1];
if(r < 0 || r >= N || c < 0 || c >= M || visit[r][c] != -1)
continue;
if(!gram && castle[r][c]==1)
continue;
if(end.r == r && end.c == c)
{
princess = true;
}
if(getGram && castle[r][c]==2)//그람을 가질것인지 true 이면, 그람 찾으면 그람에서 시작하기
{
gram = true;
que.clear();
que.add(new Pos(r,c));
int temp = visit[cur.r][cur.c]+1;
for(int j = 0; j < N; ++j)
{
Arrays.fill(visit[j], -1);
}
visit[r][c] = temp;
break;
}
que.add(new Pos(r, c));
visit[r][c] = visit[cur.r][cur.c]+1;
}
}
if(T < visit[end.r][end.c] || !princess)
return Integer.MAX_VALUE;
else
return visit[end.r][end.c];
}
}