const fs = require("fs");
const input = fs.readFileSync("/dev/stdin").toString().trim().split("\n");
let answer = [];
let strArr = input.map((str) => str.split(""));
let totalNum = 0;
let pros = {
I: 1,
V: 5,
X: 10,
L: 50,
C: 100,
D: 500,
M: 1000,
};
for (let i = 0; i < 2; i++) {
let sum = 0;
for (let j = 0; j < strArr[i].length; j++) {
if (strArr[i][j] === "I" && strArr[i][j + 1] === "V") {
sum += 4;
j++;
} else if (strArr[i][j] === "I" && strArr[i][j + 1] === "X") {
sum += 9;
j++;
} else if (strArr[i][j] === "X" && strArr[i][j + 1] === "L") {
sum += 40;
j++;
} else if (strArr[i][j] === "X" && strArr[i][j + 1] === "C") {
sum += 90;
j++;
} else if (strArr[i][j] === "C" && strArr[i][j + 1] === "D") {
sum += 400;
j++;
} else if (strArr[i][j] === "C" && strArr[i][j + 1] === "M") {
sum += 900;
j++;
} else {
sum += pros[strArr[i][j]];
}
}
totalNum += sum;
}
answer.push(totalNum);
//알파벳 구하기
let thousandNum = Math.floor(totalNum / 1000);
let thousandStr = "M".repeat(thousandNum);
totalNum -= 1000 * thousandNum;
let hundredNum = Math.floor(totalNum / 100);
let hundredStr = "";
totalNum -= 100 * hundredNum;
if (hundredNum === 4) {
hundredStr = "CD";
} else if (hundredNum === 9) {
hundredStr = "CM";
} else if (hundredNum >= 5) {
let CNum = hundredNum % 5;
hundredStr = "D" + "C".repeat(CNum);
} else {
let CNum = hundredNum % 5;
hundredStr = "C".repeat(CNum);
}
let tenNum = Math.floor(totalNum / 10);
let tenStr = "";
totalNum -= 10 * tenNum;
if (tenNum === 4) {
tenStr = "XL";
} else if (tenNum === 9) {
tenStr = "XC";
} else if (tenNum >= 5) {
let XNum = tenNum - 5;
tenStr = "L" + "X".repeat(XNum);
} else {
tenStr = "X".repeat(tenNum);
}
let oneNum = totalNum;
let oneStr = "";
if (oneNum === 4) {
oneStr = "IV";
} else if (oneNum === 9) {
oneStr = "IX";
} else if (oneNum >= 5) {
let INum = oneNum - 5;
oneStr = "V" + "I".repeat(INum);
} else {
oneStr = "I".repeat(oneNum);
}
let totalStr = thousandStr + hundredStr + tenStr + oneStr;
answer.push(totalStr);
console.log(answer.join("\n"));
100 의 자리와 10의 자리, 1의자리의 앞자리가 4나 9일때 예외 처리를 신경써주면 쉽게 풀 수 있는 문제였다.